Question

Find X if log2 (x-3) = 3​

Answer 1

Given:

Consider the given log equation

$\log_{2}{(x-3)=3}$

Find:

Need to find the value of x

Solution:

We have

$\log_{a}{(b)=c}\\b=a^c$

Therefore apply this into given equation

x- 3 = 2^3

x = 3  + 8

x = 11

Answer 2

The value of x = 11

Correct question : Find x if log₂(x - 3) = 3

Given :

The equation log₂(x - 3) = 3

To find :

The value of x

Solution :

Step 1 of 2 :

Write down the given equation

Here the given equation is

log₂(x - 3) = 3

Step 2 of 2 :

Find the value of x

$\displaystyle \sf{ log_{2}(x - 3) = 3 }$

$\displaystyle \sf{ \implies (x - 3) = {2}^{3} \: \: \: \bigg[ \: \because \: log_{m}(n) = a \: implies \: n = {m}^{a} \bigg] }$

$\displaystyle \sf{ \implies (x - 3) = 8}$

$\displaystyle \sf{ \implies x= 8 + 3}$

$\displaystyle \sf{ \implies x= 11}$

Hence the required value of x = 11

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