Question

Find 'x'if log2 (x² - 6x +40) = 5​

Answer 1

Answer:

x = 2,4

Step-by-step explanation:

given, log₂ (x² - 6x +40) = 5​

=> log₂ (x² - 6x +40) = 5​* log₂2       ( ∵ log₂2 = 1 )

=> log₂ (x² - 6x +40) = log₂2⁵

=> log₂ (x² - 6x +40) = log₂32

=> x² - 6x +40 = 32

=> x² - 6x +40 - 32 = 0

=> x² - 6x + 8 = 0

=> x² - 2x - 4x + 8 = 0

=> x (x - 2) - 4 (x - 2) = 0

=> (x - 2)(x - 4)  = 0

=> x-2 = 0   => x=2

 or x-4=0 => x = 4