Question

find x if log5 base 10 = . 699 and logx base 10 = . 233​

Answer 1

Answer:

cubth root of 5

Step-by-step explanation:

given: log5 base 10 = 0.699 -----> 1

logx base 10 = 0.233 ------> 2

divide equation 2 with equation 1.

logx base 10 / log 5 base 10 = 0.233/0.699

from the formula, log a base c / log b base c = log a base b

( note: this is only applicable when base is same)

log X base 5 = 1/3

from the log definition, if log a base b = c, then b^ c = a

here X = 5^ 1/3

=

$\sqrt[3]{5 }$