Question

find x if point Q(0,1) is equidistant from the point P(5,-3) and R(x,6)​

Answer 1

Answer:

$x = 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 4$

Step-by-step explanation:

$\sqrt{ {(5 - 0)}^{2} + {(1 + 3)}^{2} } = \sqrt{ {x}^{2} + {(6 - 1)}^{2} } \\ 25 + 16 = {x}^{2} + 25 \\ \\ {x}^{2} = 16 \\ \\ x = 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 4$