Question

Find ‘x’, if point Q(0, 1)is equidistant from the points P(5, −3) and R(, 6),I ​

Answer 1

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As given  Q(0,1) is equidistant from P(5,−3) and R(x,6)

⇒PQ=QR

⇒(0−5)2+(1−(−3))2=(x−0)2+(1−6)2    [ By using disatnce formula =(x2−x1)2+(y2−y1)2 ]

⇒25+16=x2+25

⇒41=x2+25

⇒x2=16

⇒x=4

Distance between Q(0,1) and R(4,6)

QR=(4−0)2+(6−1)2=42+52=16+25=41