Question

Find x if: $(-1/4)^{3x}\times (-1/4)^2=(-1/4)^{x-6}$

Answer 1

$( { - \frac{1}{4} })^{3x} \times ( { - \frac{1}{4} })^{2} = ( { - \frac{1}{4} })^{x - 6} \\ \\ ( { - \frac{1}{4} })^{3x + 2} = ( { - \frac{1}{4} })^{x - 6} \\ \\ 3x + 2 = x - 6 \\ \\ 2x = - 8 \\ \\ x = - 4$