Question

find x if
$( - 6) {}^{5} \times ( - 6) {}^{3 - x} = ( - 6) {}^{3}$
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Answer 1

Step-by-step explanation:

$=> {( - 6)}^{5} \times {( - 6)}^{3 -x } = {( - 6)}^{3} \\ {( - 6)}^{5 + 3 - x} = {( - 6)}^{3} \\ {( - 6)}^{8 - x} = {( - 6)}^{3} \\ \\ since \: base \: are \: same \: then \: we \: equate \: the \: power \: . \\ \\ 8 - x = 3 \\ x = 8 + 3 \\ x = 11$

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Answer 2

x = 5

Step-by-step explanation:

By using exponent property $(a^m\times a^n = a^m+n)$

Let m and n be number that is not equal to 0 and m and n be any integers.

We also assume that no denominator is equal to 0.

Then,

$(-6)^5\times(-6)^{3-x}=(-6)^3\\6^{5+3-x}=6^3\\6^{8-x}=6^3\\8-x=3\\-x=3-8\\x=5$