Question

Find x, if:
$\frac{1}{4!}+\frac{3}{6!}=\frac{x}{8!}$

Answer 1

1/4 + 1/2 = x/8
1+2/4 = x/8
3×8/4 = x
3×2 = x
6 = x
#hope it help uh

Answer 2

Answer:

x = 1848

Step-by-step explanation:

In this question

We need to find the value of x if

$\frac{1}{4!}\ +\ \frac{3}{6!}\ =\ \frac{x}{8!}$

Taking L.C.M we get,

L.C.M of 4! and 6! will be 6!

$\frac{6\times 5\ +\ 3}{6!}\ =\ \frac{x}{8!}$

$\frac{33}{6!}\ =\ \frac{x}{8\times 7\times 6!}$

$\frac{33}{6!}\ =\ \frac{x}{56\times 6!}$

6! cancels out from both the sides and cross multiplying we get,

$33\times 56\ =\ x$

$1848\ =\ x$

Hence the value of x = 1848