Math, asked by fortnite731, 4 days ago

find x if \frac{2^{2x-2}}{8}= 32

Answers

Answered by Anonymous
9

Answer:

X = 5

Step-by-step explanation:

  • We are asked to find the value of x in \frac{2^{2x-2}}{8}= 32
  • We will use the exponential rules to work out this amazing problem.
  • We will also have to change few digits in the power of 2 such as 8 and 32

\hookrightarrow Let's proceed !!

\frac{2^{2x-2}}{8}= 32

 \frac{ {2}^{(2x - 2)} }{ {2}^{3} }  = 32

{ \because 8 =  {2}^{3} }

Now, let's use the exponential rule:

 \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}

We get

 {2}^{(2x - 2) - 3}  = 32

Now,

{ 32 =  {2}^{5} }

\therefore we get

 {2}^{2x - 5}  =  {2}^{5}

Since, bases are same at both sides, we have

2x - 5 = 5

2x = 10

x \:  =  \frac{10}{2}

\therefore x = 5

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