Question

Find x if
$\frac{ {23}^{9} - {23}^{8} }{22} = {23}^{x}$
​please answer it is very very important and an emergency

Answer 1

Answer:

Step-by-step explanation:

$23^{9}$(23-1)/22=$23^{x}$

$23^{9}$x22/22=$23^{x}$

$23^{9}$=$23^{x}$

Hence x=9

Answer 2

Step-by-step explanation:

let's see this way

23=a

22=b

therefore equation is like

${a}^{9} - {a}^{8} \div b = {a}^{8} ( a - 1) \div b = {a}^{x} \: \: \\ = > therefore \: {23}^{8} (23 - 1) \div 22 = {23}^{x} \: \\ = > {23}^{8} (22) \div 22 = 1 \div {23}^{ - x} \\ = > {23}^{8} \times {23}^{ - x} = 1 \\ = > {23}^{8 - x} = {23}^{0} \\ therefore \:8 - x = 0 = > - x = - 8 = > x = 8$