Question

Find x, if the angles of a triangle are :

x°, 2x°, 2xº​

Answer 1

Answer:

The angles of a triangle are x,2x,3x.

Sum of angles of the triangle is 180

o

Thus, x+2x+3x=180

o

⟹6x=180

⟹x=

6

180

⟹x=30

As x=30

The angles of the triangle are, 30

o

,60

o

and 90

o

Since, one of the angles of the triangle is 90

o

. It is a right angled triangle.

Since, all the angles of the triangle are different, Hence all the sides of the triangle will be different. Hence, it is a right angled scalene triangle.

Answer 2

Given :

• Angles in triangle are (x)⁰,(2x)⁰and (2x)⁰

To Find :

• Value of x .

Solution :-

• As we know that sum of all angles of triangle is 180⁰.

$\sf \implies x + 2x + 2x = 180$

$\sf \implies 5x = 180$

$\sf \implies x = \cancel{\dfrac{180}{5}}$

$\implies\boxed {\bf{ x = 36}}$

Therefore angles are ,

• $\sf \: {(x)}^{\circ} \: = {36}^{\circ}$
• $\sf \:{(2x)}^{\circ} = (2\times36) = {72}^{\circ}$
• $\sf \: {(2x)}^{\circ} = (2\times36) = {72}^{\circ}$

Let's verify :

$\implies \sf \: {(x)}^{\circ} +{(2x)}^{\circ}+{(2x)}^{\circ} = {180}^{\circ}$

$\implies\sf \: {36}^{\circ} + {72}^{\circ}+ {72}^{\circ}= {180}^{\circ}$

$\implies \tt {180}^{\circ} = {180}^{\circ}$

$\huge{\therefore}$ Verified.