find x if the distance between the points (x,2) and (3,4) be 8 uniys
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x1=x, y1=2, x2=3, y2=4
Distance formula
= √[(x2-x1)²+(y2-y1)²
√[(3-x)²+(4-2)² = 8
√(9+x²-6x+4) = 8
x²-6x+13 = 8
x²-6x+5 = 0
x²-x-5x+5 = 0
x(x-1)-5(x-1) = 0
(x-1)(x-5) = 0
x-1=0 OR x-5=0
x=1 OR x=5
Therefore, x could be (1)or(5).
Distance formula
= √[(x2-x1)²+(y2-y1)²
√[(3-x)²+(4-2)² = 8
√(9+x²-6x+4) = 8
x²-6x+13 = 8
x²-6x+5 = 0
x²-x-5x+5 = 0
x(x-1)-5(x-1) = 0
(x-1)(x-5) = 0
x-1=0 OR x-5=0
x=1 OR x=5
Therefore, x could be (1)or(5).
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