Math, asked by aaliyan22, 10 months ago

find x if the value between (1,-2) and (4,y) is 5​

Answers

Answered by arun7266
1

Answer:

Step-by-step explanation:

Distance formula is√(x2-x1)² -(y2-y1)²

√(4-1)²-(y+2)²=5

√(3)²-√(y+2)²=5

3-y+2=5

5-y=5

Y=0

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Answered by codiepienagoya
0

Given:

points (1-2) and (4,y)

d=5

To find:

y=?

Solution:

Formula:

\bold{\ distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\

put the given value in the above formula:

x_1= 1\\y_1=-2\\x_2=4\\y_2=y\\\\ \to 5 =\sqrt{(4-1)^2+(y-(-2))^2}\\\\\to 5 =\sqrt{(3)^2+(y+2)^2}\\\\  \to 5= \sqrt{9+y^2+4+2y}\\\\  \to 5= \sqrt{13+y^2+2y}\\\\

square the above value:

\to 25= 13+y^2+2y\\\\\to 12= y^2+2y\\\\\to y^2+2y-12=0\\\\\to y^2+2y-12=0\\\\

apply formula:

\to \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a= 1\\b=2\\c=-12\\\\\to y= \frac{-2\pm\sqrt{4+48}}{2}\\\\\to y= \frac{-2\pm\sqrt{52}}{2}\\

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