find 'x' if x^2 - x=2
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Hi...☺
Here is your answer...✌
x² - x = 2
x² - x - 2 = 0
x² - 2x + x - 2 = 0
x(x - 2) + 1(x - 2) = 0
(x + 1) (x - 2) = 0
=> x + 1 = 0 or x - 2 = 0
=> x = -1 or x = 2
Here is your answer...✌
x² - x = 2
x² - x - 2 = 0
x² - 2x + x - 2 = 0
x(x - 2) + 1(x - 2) = 0
(x + 1) (x - 2) = 0
=> x + 1 = 0 or x - 2 = 0
=> x = -1 or x = 2
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