Question

find x if √x/√5=√2+1​

Answer 1

hope this answer helps you and plz follow me.

Answer 2

Answer:

$x = 15 + 10\sqrt{2}$

Step-by-step explanation:

$\dfrac{\sqrt{x} }{\sqrt{5}}=\sqrt{2} + 1$

Multiply both sides by √5:

$\sqrt{x} = \sqrt{5} (\sqrt{2} + 1 )$

Distribute √5:

$\sqrt{x} = \sqrt{10} + \sqrt{5}$

Square both sides:

$(\sqrt{x})^2 = (\sqrt{10} + \sqrt{5} )^2$

Apply (a + b)² = a² + b² + 2ab:

$x = (\sqrt{10} )^2 + (\sqrt{5})^2 + 2(\sqrt{10} )(\sqrt{5})$

Evaluate each term:

$x = 10 + 5 + 2\sqrt{50}$

Simplify:

$x = 15 + 10\sqrt{2}$