find x if x = tens digit of 476^1839-424^186
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Given x = tens digit of 476^1839-424^186
To find : Value of x
Solution:
476¹⁸³⁹
number ending with 76 raised to any power will end with 76
=> 476¹⁸³⁹ will end with 76
424¹⁸⁶
= 424²ˣ⁸³
= (( 424)²)⁸³
Square of number ending with 24 will end in 76
= (number ending with 76)⁸³
= will end with 76
476¹⁸³⁹ - 424¹⁸⁶ = number ending with 76 - number ending eith 76
= number ending with 00
Hence tens digit of will be 0
=> x = 0
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