Question

Find x in 3x - 2(x+3)/3 = 16 - (x+2)/2

Answer 1

Answer:

Hope it may help you.....

Answer 2

$Given\: simple \: equation :$

$3x - \frac{2(x+3)}{3} = 16 - \frac{(x+2)}{2}$

$Find \:the \: L.C.M \:of \: denominators \:3$

$and \: 2$

$L.C.M (3,2) = 6$

/* Multiplying equation by 6 , we get */

$\implies 6\Big( 3x - \frac{2(x+3)}{3} \Big)=6\Big( 16 - \frac{(x+2)}{2}\Big)$

$\implies 18x - \frac{6 \times 2(x+3)}{3} = 96 - 6 \times \frac{(x+2)}{2}$

$\implies 18x - 2\times 2(x+3) = 96 - 3(x+2)$

$\implies 18x - 4(x+3) = 96 - 3x - 6$

$\implies 18x - 4x - 12 = 90 - 3x$

$\implies 14x + 3x = 90 + 12$

$\implies 17x = 102$

$\implies x = \frac{102}{17}$

$\implies x = 6$

Therefore.,

$\red{ Value \:of \:x } \green {= 6}$

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