Question

Find x in (4x+7)/(2x+6) = (6x+5)/(3x+5)

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{(4x + 7)}{(2x + 6} = \frac{(6x + 5)}{(3x + 5)} \\ = \frac{(4x + 7)}{(2x + 6)} - \frac{(6x + 5)}{(3x + 5)} = 0\\ tak e \: a \:lcm \\ = \frac{(4x + 7)(3x + 5) - (6x + 5)(2x + 6)}{(2x + 6)(3x + 5)} = 0 \\ = \frac{ {12x}^{2} + 20x + 21x + 35 - ( \frac{}{} {12x}^{2} + 36x + 10x + 30) }{ {6x }^{2} + 10x + 18x + 30 } = 0 \\ = \frac{ {12x}^{2} + 41x + 35 - {12x}^{2} - 46x - 30 }{ {6x}^{2} + 28x + 30} = 0 \\ = \frac{5 - 5x}{ {6x}^{2} + 28x + 30} = 0 \\ take \: a \: denominator \: to \: rhs \: its \: become \: zero \\ = 5 - 5x = 0 \\ 5 = 5x \\ x = 1$

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