Question

find X in a triangle ABC if angle A is equals to 53 degrees and external angle ACD = 106°​

Answer 1

Answer:

let the angle B=x

the sum of an triangle =180degree

Step-by-step explanation:

therefore, angle A + angle B + angle c=180

53+x+106=180

x +159=180

x=180-159

x=21

:.angle B=x

:.angle B =21degree

please mark me as brainlist

Answer 2

Answer:

value of angle x = 53°

Step-by-step explanation:

in a triangle ABC ;

∠A = 53°

exterior angle ACD

∠ACD = 106°

so , let the two angles opposite to exterior ∠ACD are ∠A and ∠B

let the ∠B = x

according to formula :

exterior angle is equal to sum of two opposite interior angles of a triangle.

∠ACD = ∠A + ∠B

106 = 53 + x

x = 106 - 53

x = 53°

value of angle x = 53°