find x in a ∆xyz in which angle y=2x+7° and angle z=45°
Answers
Answered by
20
y=2x+7° and z=45°
x= 2x+7°+45°=180°
2x+52°=180°
2x=128°
x=128/2
x=64°
x= 2x+7°+45°=180°
2x+52°=180°
2x=128°
x=128/2
x=64°
Answered by
38
Answer:
Step-by-step explanation:
It is a isoceles triangle
So,
XY=XZ
Y=Z
2x + 7 =45
2x= 45-7
2x=38
x=38/2
x=19
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