find x in angle AB is (3x+18)⁰ and angle BC is 93⁰
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Answer:
3x + 18° and 2x + 25° are supplementary angles
∴ 3x + 18° + 2x + 25° = 180°
⇒ 5x + 43° = 180°
⇒ 5x =180° - 43° = 137°
⇒ x = 137/5 = 27.4° or 27° 24’
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