Question

find x in each figure:

Answer 1

$\huge {\boxed {\boxed {Answer:-}}}$

a) $\angle{BAC}=180°-90°=90°$

And $\angle{BCA}=180°-150°=30°$

We know that ,

Exterior angle =Sum of the two opp. angles

$\implies x=\angle{BAC}+\angle{BCA}$

x=90°+30°=120°

b)For this one find $\angleQRS$ and subtract it from 180°

c)For this find angle DEF and subtract from 180°

Answer 2

Answer:(A)-  angle(BAC)=90

angle(BCA)=180-150=30 (by linear pair)

now by angle sum property in triangle(ABC)

angle(ABC)+angle(BCA)+angle(CAB)=180

90+30+angle(ABC)=180

angle(ABC)=60

now by linear pair

angle(ABC)+angle(x)=180

60+x=180

x=180-60

x=120