find X in each of the following circles with centre with statement and reason
Please solve this tommorow is my exam
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Answer:
in question 5 answer is 35
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Answer:
X = 50°
Explanation:
Q6) Theorem Used :
Angle subtended by a chord at the centre of a circle is twice the angle subtended by the chord at any point on the circle.
Therefore,
Angle AOB = 2 × Angle ACB = 2 × 40° = 80°
In triangle AOB,
Angle OAB = Angle OBA
(Angles opp. to equal sides in a triangle are equal)
So, Angle OBA = X
Now,
X + 80° + X = 180°
(angle sum property of a triangle)
2x = 180° - 80° = 100°
x = 100°/2 = 50°
I hope you understood :)
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