find X in each of the following figuresthere are two part one is force and one is V give the answer separately
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(iv)
Given AB = AC
=> angle ABC = angle ACB (angles opposite to equal sides are equal in a isosceles triangles)
Now,
angle ABC = 180 - 120 (Linear pair)
=> angle ABC = 60°
=> angle ACB = angle ABC = 60°
Now,
x + angle ACB + angle ABC = 180° (Angle sum property of a ∆)
=> x + 60 + 60 = 180
=> x = 180 - 120
=> x = 60°
(v)
Now name the triangle as ABC where angle B = x
Now angle C = 180 - 130 (linear pair)
=> angle C = 50°
Angle A = 180 - 100 (linear pair)
=> angle A = 80°
Again, x + angle A + angle B = 180° (angle sum property)
=> x + 80 + 50 = 180°
=> x = 180 - 130
=> x = 50°
Hope it helps dear friend ☺️✌️✌️
Given AB = AC
=> angle ABC = angle ACB (angles opposite to equal sides are equal in a isosceles triangles)
Now,
angle ABC = 180 - 120 (Linear pair)
=> angle ABC = 60°
=> angle ACB = angle ABC = 60°
Now,
x + angle ACB + angle ABC = 180° (Angle sum property of a ∆)
=> x + 60 + 60 = 180
=> x = 180 - 120
=> x = 60°
(v)
Now name the triangle as ABC where angle B = x
Now angle C = 180 - 130 (linear pair)
=> angle C = 50°
Angle A = 180 - 100 (linear pair)
=> angle A = 80°
Again, x + angle A + angle B = 180° (angle sum property)
=> x + 80 + 50 = 180°
=> x = 180 - 130
=> x = 50°
Hope it helps dear friend ☺️✌️✌️
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