Question

find x in each of the following



please answer my question​

Answer 1

Given

∠ABC=x+10°

∠BAC=x

∠ACB=x-10°

Find

Value of x

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Step by step explanation

1. We have given three angles of a triangle and we have to find x.Recall property of triangle where all the sum of the angles in a triangle is 180°.So, we use this property here and we find the value of x.

∠ABC+∠BAC+∠ACB=180°

x+10°+x+x-10°=180°

=>3x=180°

=>X=180/3

X=60

∠ABC=x+10°=60+10°=70°

∠BAC=60°

∠ACB=x-10°=60°-10=50

∠ABC+∠BAC+∠ACB=180°

=>70°+60°+50°=180°

Answer 2

Answer:

❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

∠ABC+∠BAC+∠ACB=180°

x+10°+x+x-10°=180°

=>3x=180°

=>X=180/3

X=60

∠ABC=x+10°=60+10°=70°

∠BAC=60°

∠ACB=x-10°=60°-10=50

∠ABC+∠BAC+∠ACB=180°

=>70°+60°+50°=180°