Question

find X in log x=4.8 291​

Answer 1

SOLUTION

TO DETERMINE

The value of x when

$\sf{ \log x = 4.8291}$

FORMULA TO BE IMPLEMENTED

We are aware of the formula on logarithm that

$\sf{ log_{a}(x) = m \: \: \: implies \: \: \: x = {a}^{m} }$

EVALUATION

Here the given that

$\sf{ \log x = 4.8291}$

Taking base as 10

$\sf{ log_{10}(x) = 4.8291 }$

$\implies \sf{x = {10}^{4.8291} }$

$\implies \sf{x = 67468.34 }$

Taking base as e

$\sf{ log_{e}(x) = 4.8291 }$

$\implies \sf{x = {e}^{4.8291} }$

$\implies \sf{x = 125.09 }$

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