Question

Find 'x' in the first three equations please very urgent​

Answer 1

Answer:

1)YOUR QUESTIONS IS WRONG BECAUSE -

In tri TSQ = 95 +x+Q =180

n tri QRP = 90+x+Q =180

This is impossible because two terms that is x and Q are same and that makes The left out angle also same in both the cases whereas the figure u drew shows the angles to be different.

2) Given-

P = 40

R= 50

:. angle POR = 70 +50 + o = 180 ( angle sum property)

120+o= 180

o = 180-120

o= 60 degrees

We know that vertically opposite angles are always equal :. Angle OPR = SOQ = 60 degrees

Now using the angle sum property= 60+80+x = 180

=> 140+x=180

:. x= 180-140= 40 degrees

3) We know 110 , 30 and the other angle add up to 180 as they are supplementary pair of angles which means 110+30+DAC= 180

140 + DAC = 180

180 - 140 = DAC

:.DAC = 40

We know that base angles of an isosceles triangle are always equal :. Angle B = 30

Using the angle sum property we say 30 +30+ ADB = 180

60 +ADB= 180

180 - 60 =ADB

120 = ADB

Now ADB + ADC = 180

120 +ADC= 180

180-120= ADC

60 = ADC

Now using the angle sum property we say in triangle ADC

DAC+ ADC+x = 180

40 + 60 +x= 180

100+x = 180

:. x= 180-100

:.x= 80 degrees

 

Answer 2

....x = 40 degrees....