Math, asked by shrijani2018, 3 months ago

Find x in the follor
given triangle​

Attachments:

Answers

Answered by TwilightShine
8

Answer :

  • The value of x = 36°.

Given :-

  • The angles of the triangle are (2x - 40)°, (3x - 80)° and (5x - 60)°.

To find :-

  • The value of x.

Step-by-step explanation :-

We know the value of the angles in the triangle.

The sum of all the angles in a triangle = 180°.

Thus, we get :-

\sf(2x - 40)^{\circ} + (3x - 80)^{\circ} + (5x - 60)^{\circ} = 180^{\circ}.

On removing the brackets,

\sf2x^{\circ}  + (- 40)^{\circ} + 3x^{\circ}  + (- 80)^{\circ} + 5x^{\circ}  +  ( - 60)^{\circ} = 180^{\circ}

On putting the constants and variables separately,

\sf2x^{\circ} + 3x^{\circ} + 5x^{\circ}  +  ( - 40)^{\circ}  + (- 80)^{\circ} + (- 60)^{\circ} = 180^{\circ}

On simplifying,

\sf10x^{\circ}  +  ( - 180)^{\circ} = 180^{\circ}

(+) and (-) = (-), so :-

\sf10x^{\circ} - 180^{\circ} = 180^{\circ}

Transposing 180 from LHS to RHS, changing its sign,

\sf10x^{\circ} = 180^{\circ} + 180^{\circ}

On simplifying,

\sf10x^{\circ} = 360^{\circ}

Transposing 10 from LHS to RHS, changing its sign,

\sf x =  \dfrac{360^{\circ}}{10^{\circ}}

Dividing 360 by 10,

\sf x = 36^{\circ}.

Therefore, x = 36°.

Therefore, the value of each angle :-

(2x - 40)° = (2 × 36° - 40°) = 32°.

(3x - 80)° = (3 × 36 - 80°) = 28°.

(5x - 60)° = (5 × 36° - 60°) = 120°.

______________________________________

Verification :-

(Optional)

To check our answer, we just have to put 36 (value of x) in place of x and check whether the LHS = RHS.

We can also check by adding the value of all the angles and see whether we get 180° or not (The sum of all the angles in a triangle).

32° + 28° + 120° = 180°.

Since the sum of all the angles is 180°,

Hence verified! ✔️✔️

______________________________________

Note :- Kindly view this answer from the website for better experience. However, you can view the answer from the app too.


BrainlyPhantom: Nyc!
TwilightShine: Thanks! :)
Anonymous: Nice
TwilightShine: Thanks! :)
Similar questions