find x in the following
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Answer:-
x = 20°
Step-by-step explanation:-
∵ ∠ABO = 3x + 10°
∴ ∠AOB = 3x + 10° (∠s opposite to equal sides are equal)
⇒ ∠COD = 3x + 10° (VERTICALLY OPPOSITE)
Now, in ΔCOD,
∠COD + ∠DCO + ∠CDO = 180° ( ANGLE SUM PROPERTY OF A TRIANGLE )
→ 3x + 10 + 2x + 3x + 10 [∠COD = ∠CDO(∵∠s opposite to equal sides are equal)] = 180°
⇒ 8x + 20 = 180°
→ 8x = 160 °
⇒ x = 20°
Hope it helps u :)
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