Question

find x in the following figure
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Answer 1

Answer:

In the ∆ AOB

Two angles: 70°,6

So, 70°+60°+angle AOB = 180°(ASP)

=> angle AOB = 180°-70°-60°

=> angle AOB = 50°---------------(1)

So, angle AOB + angle BOE = 180°

=> angle BOE = 180°-50°

=> angle BOE = 130°--------------(2)

So, angle BOE + angle EOD = 180°

=> angle EOD = 180°-130°

=> angle EOD = 50°---------------(3)

So, angle AOB + angle AOD = 180°

=> angle AOD = 180°-50°

=> angle AOD = 130°--------------(4)

So, angle AOD + angle DOE = 180°

=> angle DOE = 180°-130°

=> angle DOE = 50°---------------(5)

In the ∆ EOD

x° + angle EOD + angle DOE = 180°(ASP)

=> x° + 50° + 50° = 180°

=> x° = 180°-100°

=> x° = 80° (ANS)