Question

Find x in the given Angle ABC, where AC = BC and Angle ACD = 130º.​

Answer 1

Answer:

Consider this< as angle

<ACD= 130

So <ACD+ < ACB =180 ( linear pair)

130 + < ACB = 180

BY USING TRANSPOSITION METHOD

< ACB = 180 -- 130

= 50

As angle AC = BC

Then angle 50 = < B

SO < B = 50

NOW. :- <A + <B + <C = 180 ( BY USING ANGLE SUM PROPERTY.)

X + 50 + 50 =180

X + 100= 180

X = 180 - 100

X = 80