Question

Find x in the given equation:

Answer 1

Step-by-step explanation:

Your question:

$\frac{( - 7) ^{6x} }{ - {49}^{3} } = - {7}^{12}$

Your answer:

$\frac{ - {7}^{6x} }{ - {7}^{6} } = { - 7}^{12}$

[ now divide the fraction]

${ - 7}^{6x - 6} = { -7 }^{12}$

[ now cancel negative sign and 7]

$6x - 6 = 12$

[ now take 6 to RHS]

$6x = 12 + 6$

[ now divide 6 to 12 + 6]

$x = \frac{12 + 6}{6}$

[ add 12 and 6 ]

$x = \frac{18}{6}$

[ divide 18 by 6]

$x = 3$

Your final answer: 3

Answer 2

Step-by-step explanation:

$\frac{( { - 7}^{6x} )}{ { - 49}^{3} } = ( { - 7})^{12} \\ \frac{ { - 7}^{6x} }{ { { - 1 \times ( 7 }^{2} })^{3} } = { - 7}^{12} \\ \frac{ - 1 \times { 7}^{6x - 6} }{ - 1} \\ {7}^{6x - 6} = { - 7}^{12} \\ - 7 \: cancel \: from \: both \: side \\ 6x - 6 = 12 \\ 6x - 6 = 12 \\ 6x = 12 + 6 \\ x = \frac{18}{6} \\ x = 3$

identity used=a^m÷a^n=a^m-n