Question

find x in the given fig.

Answer 1

Step-by-step explanation:

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Answer 2

Solution :-

$\implies log_4x + log_2x = 6$

$\implies log_{2^2}x + log_2x = 6$

By applying the property of log.

$\implies \dfrac{1}{2}log_4x + log_2x = 6$

Let us denote $log_2x$ with a variable k

$\implies \dfrac{1}{2}k + k = 6$

$\implies k \left( \dfrac{1}{2} + 1 \right) = 6$

$\implies k \dfrac{3}{2} = 6$

$\implies k = \dfrac{2}{3} \times 6$

$\implies k = 4$

Now by solving log

$\implies log_2x = 4$

$\implies x = 2^4$

$\implies x = 16$