find x in the given figure.
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in triangle ABC
angle ABC + ACB + bac =180°(angle sum property)
ABC +70+30=180
abc=180-100=80
ABC=2(DBC)
80/2=DBC =40
in triangle DBC
DBC + BCD +cdb =180°
40+70+4x+x=180
5x=180-110
x=70/5=14
4x=4(14)=56
angle ABC + ACB + bac =180°(angle sum property)
ABC +70+30=180
abc=180-100=80
ABC=2(DBC)
80/2=DBC =40
in triangle DBC
DBC + BCD +cdb =180°
40+70+4x+x=180
5x=180-110
x=70/5=14
4x=4(14)=56
gunjan010773p2afz3:
in my book 14 is the answer
not 56
x=14 answer is correct only
then 56???
56 is wat
it is for angle ACD
so wat should i write
14 or 56
u write that x=14
okay tysm
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