find x in the given figure.
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in triangle ABC
angle ABC + ACB + bac =180°(angle sum property)
ABC +70+30=180
abc=180-100=80
ABC=2(DBC)
80/2=DBC =40
in triangle DBC
DBC + BCD +cdb =180°
40+70+4x+x=180
5x=180-110
x=70/5=14
4x=4(14)=56
angle ABC + ACB + bac =180°(angle sum property)
ABC +70+30=180
abc=180-100=80
ABC=2(DBC)
80/2=DBC =40
in triangle DBC
DBC + BCD +cdb =180°
40+70+4x+x=180
5x=180-110
x=70/5=14
4x=4(14)=56
gunjan010773p2afz3:
in my book 14 is the answer
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