find X in the given figure
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khushi4524:
x=14
with process
30 + 70 + angle ABC= 180THEN Angle ABC= 80And angleDBC=40 then 40+ 70 +4x+x=180 then on solving we will get x=14
ty so much
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X=14
mark brainliest thanks
mark brainliest thanks
Attachments:
with process
wait
mark brainliest then
30+70+ b=180
30+40 =70exterior angle now linear line make 180 so you get 110from there
110+5x =180 x=14
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Answered by
3
Dear friend,
Here's your answer...
In ΔABC, angle BAC = 30° , angle ACB = 70°
angle ABC = ?
By angle sum property of a Δ,
angle BAC + angle ACB + angle ABC = 180°
30° + 70° + angle ABC = 180°
angle ABC = (180 - 100)° = 80°
Now in ΔDBC,
angle BDC = x , angle DBC = 1/2 ang. ABC = 80/2 = 40°and angle DCB = 70°+ 4x
By angle sum property of a Δ
angle BDC + angle DBC + angle DCB = 180°
x + 40° + 70° + 4x = 180°
5x = 180°- 110 = 70
x = 70/5
***x = 14°
Hope it helps you!!
Here's your answer...
In ΔABC, angle BAC = 30° , angle ACB = 70°
angle ABC = ?
By angle sum property of a Δ,
angle BAC + angle ACB + angle ABC = 180°
30° + 70° + angle ABC = 180°
angle ABC = (180 - 100)° = 80°
Now in ΔDBC,
angle BDC = x , angle DBC = 1/2 ang. ABC = 80/2 = 40°and angle DCB = 70°+ 4x
By angle sum property of a Δ
angle BDC + angle DBC + angle DCB = 180°
x + 40° + 70° + 4x = 180°
5x = 180°- 110 = 70
x = 70/5
***x = 14°
Hope it helps you!!
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