find x in the given figure.
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I hope it helps mate
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in triangle ABC is Isoscele triangle (by given figure) so,hereAB=AC
Angle A=angleB=58°
by angle sum properties(sum of all angle=180°)
therefore,58°+58°+BXC=180°
116°+BXC=180°
BXC =180-116
BXC=64°
angle ACD=180°-58
ACD=122°
in triangle ACD, angle ACD=122, angle ADC=40°
angle CAD=180-122-40
CAD=18°
Therefore, angle X=64°+18°
X=82°
if the answer is right so put in brainlist
Angle A=angleB=58°
by angle sum properties(sum of all angle=180°)
therefore,58°+58°+BXC=180°
116°+BXC=180°
BXC =180-116
BXC=64°
angle ACD=180°-58
ACD=122°
in triangle ACD, angle ACD=122, angle ADC=40°
angle CAD=180-122-40
CAD=18°
Therefore, angle X=64°+18°
X=82°
if the answer is right so put in brainlist
aashish60:
please Mark my answer in brainlist
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