Question

find x in this fig
Last figure I couldn't edit
Plz answer and ur answer BRAINLIEST for sure ​

Answer 1

GIVEN:-

• $\rm{ \angle{ACB} = 30^{\circ}\angle{CAB} = 34^{\circ}}$

• $\rm{ \angle{EDB} = 45^{\circ}}$

TO FIND:-

• The Value of x.

CONCEPT USED:-

• Exterior angle Property - The sum of two interior opposite angle is equal to Exterior angle.

Now,

$\implies\rm{ \angle{ACB} +\angle{CAB} = \angle{CBD}}$( Exterior angle)

$\implies\rm{ 30^{\circ} + 34^{\circ} = \angle{CBD}}$

$\implies\rm{ \angle{CBD} = 64^{\circ}}$.

Again,

$\implies\rm{\angle{EBD} + \angle{EDB} = x}$(Exterior angle)

$\implies\rm{ 64^{\circ} + 45^{\circ} = x^{\circ}}$

$\implies\rm{ x^{\circ} = 109^{\circ}}$.

Hence, The Value of x° is 109°.

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf{ \angle{ACB} = 30 \degree \angle{CAB} = 34 \degree}$

$\sf{ \angle{EDB} = 45\degree}$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow angle\:"x"$

$\large\underline\bold{SOLUTION,,}$

ACCORDING TO THE QUESTION,

✯property in use,

$\sf{\boxed{\sf{The \:sum \:of \:two\: interior \:opposite\: angle \:is\: equal \:to\: Exterior\: angle.}}}$

$\implies\sf{ \angle{ACB} +\angle{CAB} = \angle{CBD}.......^{exterior\:angles}}$

$\implies\sf{ 30\degree+ 34 \degree = \angle{CBD}}$

$\implies\sf{ \angle{CBD} = 64\degree}$.

$\sf{\boxed{\sf{\therefore \angle{CBD} = 64 \degree }}}$

we got the value of angle ∠CBD .

NOW,

$\sf\therefore FOR\:FINDING\:ANGLE\:X,$

$\implies\sf{\angle{EBD} + \angle{EDB} = x.............^{exterior\:angle\:property.}}$

$\implies\sf{ 64\degree + 45\degree = x \degree}$

$\implies\sf{ 109\degree =x\degree }$.

$\implies\sf{ x\degree = 109\degree}$.

$\large{\boxed{\bf{ x= 109\degree}}}$

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