find x in this figure
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X+x+29+x-17=180°(linear pair)
3x=180°-12
X=168÷3
X=56
3x=180°-12
X=168÷3
X=56
aashi09:
Hey bhavya ...
Answered by
5
Hey dear!!
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In the given figure,
AOB is a straight line and ∠AOC, ∠COD and ∠DOB form a linear pair axiom.
Hence their sum would be 180°.
∴∠AOC + ∠COD + ∠DOB = 180°
x + (x + 29°) + (x - 17°) = 180°
3x + 12° = 180°
3x = 180 - 12
3x = 168°
x = 168/3
x = 56°
Therefore, ∠AOC measures 56°.
∠COD measures 85°.
And ∠DOB measures 39°.
_______________________________________________________________________________________________________________
Hope helped!!
_________________________________________________________________________________________________
In the given figure,
AOB is a straight line and ∠AOC, ∠COD and ∠DOB form a linear pair axiom.
Hence their sum would be 180°.
∴∠AOC + ∠COD + ∠DOB = 180°
x + (x + 29°) + (x - 17°) = 180°
3x + 12° = 180°
3x = 180 - 12
3x = 168°
x = 168/3
x = 56°
Therefore, ∠AOC measures 56°.
∠COD measures 85°.
And ∠DOB measures 39°.
_______________________________________________________________________________________________________________
Hope helped!!
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