Question

find x in triangle using Pythagoras ​

Answer 1

In triangle ABC

From Pythagoras theorem,

AC^2=(√34)^2+13^2

AC^2=203-------(1)

In triangle ACD

x^2=AC^2+11^2

x^2=203+121. (using 1)

x=√224=√2×2×2×2×2×7=4√14.

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