find x
log5^x+log25^x^2+log125^x^3=12
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Use loga^b= blog a
So log5+ 2log5 + 3 log5
6 xlog5= 12
X lo5 = 2
X=2/log5 2/.6021
So log5+ 2log5 + 3 log5
6 xlog5= 12
X lo5 = 2
X=2/log5 2/.6021
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