Math, asked by shaurya2856, 17 days ago

Find x of angle AOC= 70° and angle BAO = 50° where
O is centre of the circle.


please solve this question ​

Attachments:

Answers

Answered by anonymous1739
2

Answer:

option D) 15°

Step-by-step explanation:

Angle CBA = 35°

Angle ADB = 95°=CDO

x= 180-(70+85)

x = 15°

Answered by razeenrauf4
0

Answer:

d) 15 degrees

Step-by-step explanation:

Angle AOC = 70 degrees (given)

Angle BAO = 50 degrees (given)

Angle ABC = 70/2 (Central angle theorem)

= 35 degrees

Angle BAO + Angle ABC + Angle ADB = 180 degrees (Angle sum property of triangle)

50 + 35 + Angle ADB = 180 degrees

85 + Angle ADB = 180

Angle ADB = 180 - 85

Angle ADB = 95 degrees

Angle ADB = Angle ODC = 95 degrees (VOA)

Angle AOC + Angle ODC + Angle OCB = 180 degrees (Angle sum property of triangle)

70 + 95 + x = 180

165 + x = 180

x = 180 - 165

x = 15 degrees

Angle OCB = 15 degrees

Similar questions