Find x of angle AOC= 70° and angle BAO = 50° where
O is centre of the circle.
please solve this question
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Answered by
2
Answer:
option D) 15°
Step-by-step explanation:
Angle CBA = 35°
Angle ADB = 95°=CDO
x= 180-(70+85)
x = 15°
Answered by
0
Answer:
d) 15 degrees
Step-by-step explanation:
Angle AOC = 70 degrees (given)
Angle BAO = 50 degrees (given)
Angle ABC = 70/2 (Central angle theorem)
= 35 degrees
Angle BAO + Angle ABC + Angle ADB = 180 degrees (Angle sum property of triangle)
50 + 35 + Angle ADB = 180 degrees
85 + Angle ADB = 180
Angle ADB = 180 - 85
Angle ADB = 95 degrees
Angle ADB = Angle ODC = 95 degrees (VOA)
Angle AOC + Angle ODC + Angle OCB = 180 degrees (Angle sum property of triangle)
70 + 95 + x = 180
165 + x = 180
x = 180 - 165
x = 15 degrees
Angle OCB = 15 degrees
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