Find x... Please it's urgent
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hope thus helps uu.........
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first, what is 25^(5/2)?
we can write it as (5²)^(5/2)
= 5^ ( 2 x 5/2)
= 5^5
= 3125
then what is 243^(2/5)?
we can write (3^(5))^(2/5)
= 3^(5 x 2/5)
= 3^2
= 9
then what is 16^(3/4)?
we can write (2^(4))^(3/4)
= 2^ ( 4 x 3/4)
= 2^3
= 8
then 8^(5/3)
= (2^(3))^(5/3)
= 2^(3 x 5/3)
= 2^5
=32
Then finally keep them inside the question.
(3125 x 9)/(8 x 32) = x
28125/256 = x
x = 109.86
we can write it as (5²)^(5/2)
= 5^ ( 2 x 5/2)
= 5^5
= 3125
then what is 243^(2/5)?
we can write (3^(5))^(2/5)
= 3^(5 x 2/5)
= 3^2
= 9
then what is 16^(3/4)?
we can write (2^(4))^(3/4)
= 2^ ( 4 x 3/4)
= 2^3
= 8
then 8^(5/3)
= (2^(3))^(5/3)
= 2^(3 x 5/3)
= 2^5
=32
Then finally keep them inside the question.
(3125 x 9)/(8 x 32) = x
28125/256 = x
x = 109.86
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