Question

find x so that [(1/3)^-2 * (1/3)^-5] = (1/3)^2x +1

Answer 1

Answer:

x=−3.499792

Step-by-step explanation:

Hmm... Looks complicated. But we will solve it :-)

=>[(1/3)^{-2}*(1/3)^-5]=(1/3)^{2x}+1

=>2187=( 1 /3 )^2x+1

Step 1: Flip the equation

=>( 1 /3 )^2x+1=2187

Step 2: Add -1 to both sides.(transposition)

=>( 1 /3 )^2x+1−1=2187−1

=>( 1 /3 )^2x=2186

Step 3: Solve Exponent.

( 1 /3 )^2x=2186

log(( 1 /3 )2x)=log(2186) (Take log of both sides)

2x*(log( 1 /3 ))=log(2186)

2x= (log(2186))/ (log( 1 /3 ))

2x=−6.999584

(2x) /2 = −6.999584 /2  (Divide both sides by 2)

x=−3.499792

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