Math, asked by Tanay2909, 1 year ago

Find X so that (2/3^-2).......​

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Answered by spp84
3

as base is same , add the both powers and it's became (2/3)-¹¹=(2/3)²x+¹

now again base is equal than

=-11=2x+1

=2x=-12

=x=-6

Answered by Brainly100
3

{ (\frac{2}{3} )}^{ - 2}  \times  {(\frac{2}{3} )}^{ - 9}  =  {(\frac{2}{ 3}) }^{2x + 1}  \\  \\ \implies  {(\frac{2}{3})}^{ - 2 - 9}   = {( \frac{2}{3} )}^{2x + 1}  \\  \\  \implies   - 11 = 2x + 1 \\  \\  \implies 2x =  - 12 \\  \\  \implies  \boxed{x =  - 6}

As the bases of both the fractions are equal, hence their power gets add up and at last the base becomes equal in LHS and RHS .

Therefore we can directly make the powers equal. Finally we solved the linear equation .

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