Find x so that (2/3)^-5×(2/3)^-11=(2/3)^8x
Answers
Answered by
16
Hi ,
***********************************
We know the Exponential Laws:
i ) a^m × a^n = a^m+n
ii ) If a^m = a^n then m = n
***************************************
(2/3)^-5×(2/3)^-11 = (2/3)^8x
=> (2/3)^-5-11 = (2/3)^8x
=> ( 2/3 )^-16 = (2/3)^8x
=> -16 = 8x
=> ( -16 )/8 = x
=> -2 = x
Therefore ,
x = -2
I hope this helps you.
: )
***********************************
We know the Exponential Laws:
i ) a^m × a^n = a^m+n
ii ) If a^m = a^n then m = n
***************************************
(2/3)^-5×(2/3)^-11 = (2/3)^8x
=> (2/3)^-5-11 = (2/3)^8x
=> ( 2/3 )^-16 = (2/3)^8x
=> -16 = 8x
=> ( -16 )/8 = x
=> -2 = x
Therefore ,
x = -2
I hope this helps you.
: )
Answered by
1
Answer:
-2 is the answer hope it helps u
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