find x so that 3/5,x and 5/3x are the three consecutive terms of AP
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Answer:
Given: (3y−1),(3y+5) and (5y+1) are 3 consecutive terms of an AP.
So, difference between two consecutive terms will be same.
(3y+5)−(3y−1)=(5y+1)−(3y+5)
2(3y+5)=5y+1+3y−1
6y+10=8y
8y−6y=10
2y=10
or y=5
The value of y is 5.
Step-by-step explanation:
hope it helps
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