Question

Find x, so that 3x+1,x2-2x+1, and 2x2-6x+2 are consecutive
terms of an AP
​

Answer 1

Answer:

x= -1

Step-by-step explanation:

since the three are consecutive terms of an AP, the common differences will be same

so second term minus first

x2-2x+1 - (3x+1) = x2-5x ---- eqn 1

third term minus second

2x2-6x+2 - (x2-2x+1) = x2-4x+1 ---eqn 2

eqn 1 = eqn 2 (common differences d is same)

x2-5x = x2-4x+1

=5x-4x = -1

therefore, x= -1

Answer 2

Answer:

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