Question

-find
x
So that
(-5)^x^1 x (-5)^5= (-5)^7​

Answer 1

${( - 5)}^{x ^{1} } \times ( - 5) {}^{5} = ( - 5) ^{7}$

$\implies \: ( - 5) {}^{x} \times {( - 5)}^{5} = {( - 5)}^{7}$

$\large\ \: \red{since \: \: the \: bases \: are \: equal , their \: powers }$

$\large\ \: \red{ will \: also \: be \: equal}$

$\implies {( - 5)}^{(x + 5)} = {( - 5)}^{7}$

$\implies \: x + 5 = 7$

$\implies \: x = 7 - 5 \\ = 2$