Question

find x so that the question

Answer 1

(1/3)^-5*(1/3)^7=(1/3)^2x-1
(1/3)^-5+7=(1/3)^2x-1 since a^m*a^n=a^m+n

Therefore
-5+7=2x-1 since if a^m=a^n then m=n
2=2x-1
3=2x
3/2=x
x=3/2

Answer 2

Since ,
x^a×x^b=x^(a+b)

(1/3)^-5×(1/3)^7=(1/3)^7-5
=(1/3)^2

And ,
if,x^a=x^b
then,
a=b

(1/3)^2=(1/3)^2x-1

So,
2=2x-1
2x=2+1
2x=3
x=3÷2
x=1.5

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