Question

Find X so that x+6 , x+12 and x+15 are consecutive terms of GP(Geometric Progression)
HELP ME !!!​

Answer 1

Answer:

Please mark this as brainliest. Answers = -12 , -6 , -3

Step-by-step explanation:

Let the terms be a1, a2, a3. For a GP, the common ratio should be same,

a2/a1 = a3/a2

Now according to question, a1 = x+6  a2=x+12  a3 = x+15

x+12 / x+6 = x+15/x+12

Cross multiplying

(x+12)(x+12) = (x+6)(x+15)

x^2 + 24x + 144 = x^2 + 21x + 90

Subtracting x^2 from both side and taking 21x from RHS to LHS and 144 from LHS to RHS

3x = -54

x = -18

The numbers = -12 , -6 , -3

Mark this answer as brainliest!!

Answer 2

Step-by-step explanation:

Hope helpful for you Mark me as brainlist please